Top 100 Bangladeshi SO user
TOP 50 StackOverflow user in Bangladesh
Top Users by Number of Bounties Won in Bangladesh
-- Top Users by Number of Bounties Won in Bangladesh
SELECT Top 150
Posts.OwnerUserId As [User Link], COUNT(*) As BountiesWon, Users.Location
FROM Votes
INNER JOIN Posts ON Votes.PostId = Posts.Id
Inner JOIN Users ON Posts.OwnerUserId = Users.Id
WHERE
VoteTypeId=9 and LOWER(Users.Location) LIKE LOWER('%Bangladesh')
GROUP BY
Posts.OwnerUserId, Users.Location
ORDER BY
BountiesWon DESC
http://meta.stackexchange.com/questions/49943/interesting-queries-on-data-explorer
SELECT Top 150
Posts.OwnerUserId As [User Link], COUNT(*) As BountiesWon, Users.Location
FROM Votes
INNER JOIN Posts ON Votes.PostId = Posts.Id
Inner JOIN Users ON Posts.OwnerUserId = Users.Id
WHERE
VoteTypeId=9 and LOWER(Users.Location) LIKE LOWER('%Bangladesh')
GROUP BY
Posts.OwnerUserId, Users.Location
ORDER BY
BountiesWon DESC
Top Users by Number of Bounties Won
-- Top Users by Number of Bounties Won SELECT TOP(100) ROW_NUMBER() OVER (ORDER BY COUNT(*) Desc) as PositionNumber, Posts.OwnerUserId As [User Link], COUNT(*) As BountiesWon FROM Votes INNER JOIN Posts ON Votes.PostId = Posts.Id WHERE VoteTypeId=9 GROUP BY Posts.OwnerUserId ORDER BY BountiesWon DESC
http://meta.stackexchange.com/questions/49943/interesting-queries-on-data-explorer
http://data.stackexchange.com/stackoverflow/revision/485914/615634/top-100-bangladeshi
Select TOP(100) ROW_NUMBER() OVER (ORDER BY Reputation Desc) as PositionNumber, Id [User Link], DisplayName, Age, Reputation, WebsiteUrl, Location
From Users
Where LOWER(Location) LIKE LOWER('%Bangladesh')
ORDER BY
Reputation DESC;
http://data.stackexchange.com/stackoverflow/query/949/what-is-my-accepted-answer-percentage-rate
-- What is my accepted answer percentage rate -- On avg how often are answers I give, accepted DECLARE @UserId int = ##UserId## SELECT (CAST(Count(a.Id) AS float) / (SELECT Count(*) FROM Posts WHERE OwnerUserId = @UserId AND PostTypeId = 2) * 100) AS AcceptedPercentage FROM Posts q INNER JOIN Posts a ON q.AcceptedAnswerId = a.Id WHERE a.OwnerUserId = @UserId AND a.PostTypeId = 2
Ranking in StackOverflow
http://data.stackexchange.com/stackoverflow/revision/478416/606174/ranking-in-stackoverflow
WITH RankingsInSO AS ( SELECT Id, RankingInSO = ROW_NUMBER() OVER(ORDER BY Reputation DESC) FROM Users ) ,CountsInSO AS ( SELECT CountInSO = COUNT(*) FROM Users WHERE Reputation > 100 ) ,Rankings AS ( SELECT Id, RankingInBangladesh = ROW_NUMBER() OVER(ORDER BY Reputation DESC), DisplayName, Age, Reputation, WebsiteUrl, Location FROM Users Where LOWER(Location) LIKE LOWER('%Bangladesh') ) ,Counts AS ( SELECT Count = COUNT(*) FROM Users WHERE Reputation > 100 and LOWER(Location) LIKE LOWER('%Bangladesh') ) SELECT R.Id, R.Id[User Link], R.RankingInBangladesh, CAST(R.RankingInBangladesh AS decimal(20, 5)) / (SELECT Count FROM Counts) AS PercentileInBangladesh, RSO.RankingInSO as RankingInSO, CAST(RSO.RankingInSO AS decimal(20, 5)) / (SELECT CountInSO FROM CountsInSO) AS PercentileInSO, R.Age, R.Reputation, R.WebsiteUrl, R.Location FROM Rankings R, RankingsInSO RSO WHERE R.Id = 2293534 and R.Id = RSO.Id
My Rank in Bangladesh
https://data.stackexchange.com/stackoverflow/revision/478354/606098/my-rank-in-bangladesh
-- StackOverflow Rank and Percentile WITH Rankings AS ( SELECT Id, RankingInBangladesh = ROW_NUMBER() OVER(ORDER BY Reputation DESC), DisplayName, Age, Reputation, WebsiteUrl, Location FROM Users Where LOWER(Location) LIKE LOWER('%Bangladesh') ) ,Counts AS ( SELECT Count = COUNT(*) FROM Users WHERE Reputation > 100 and LOWER(Location) LIKE LOWER('%Bangladesh') ) SELECT Id, Id[User Link], RankingInBangladesh, CAST(RankingInBangladesh AS decimal(20, 5)) / (SELECT Count FROM Counts) AS Percentile, Age, Reputation, WebsiteUrl, Location FROM Rankings WHERE Id = 2293534